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SQL – PADS

Generate the following two result sets:

  1. Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i.e.: enclosed in parentheses). For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S).

  2. Query the number of ocurrences of each occupation in OCCUPATIONS. Sort the occurrences in ascending order, and output them in the following format.   There are a total of [occupation_count] [occupation]s. where [occupation_count] is the number of occurrences of an occupation in OCCUPATIONS and [occupation] is the lowercase occupation name. If more than one Occupation has the same [occupation_count], they should be ordered alphabetically.

Note: There will be at least two entries in the table for each type of occupation.

Input Format

The OCCUPATIONS table is described as follows: 

 

Occupation will only contain one of the following values: Doctor, Professor, Singer or Actor.

Sample Input

An OCCUPATIONS table that contains the following records:

Sample Output

Ashely(P) 
Christeen(P) 
Jane(A) 
Jenny(D) 
Julia(A) 
Ketty(P) 
Maria(A) 
Meera(S) 
Priya(S) 
Samantha(D) 
There are a total of 2 doctors. 
There are a total of 2 singers. 
There are a total of 3 actors. 
There are a total of 3 professors.

Solution

First Query

  1. The first query wants to display the Name of the person and only the first letter of the Occupation.
  2. To find the first letter of occupation we can use LEFT() function of MYSQL and SUBSTR() function of Oracle.
  3. To give output as “Name(O)”, we can use CONCAT() function in MYSQL and CONCAT() function or concantenation operator “||” in ORACLE.
  4. We need to order the result by alphabetically by name, for that we can use ORDER BY NAME

 

MySQL

SELECT CONCAT(NAME,'(',LEFT(OCCUPATION, 1),')') 
FROM OCCUPATIONS 
ORDER BY NAME;

Oracle

SELECT NAME || '(' || SUBSTR(OCCUPATION, 0, 1) || ')' 
FROM OCCUPATIONS 
ORDER BY NAME;

Second Query

  1. To find the number of occurrences of each occupation, we can use the COUNT(*) function along with GROUP BY clause.
  2. To give output as “There are a total of 6 doctors.”, we can use CONCAT() function in MYSQL and CONCAT() function or concantenation operator “||” in ORACLE.
  3. And we can use LOWER() function to convert “Doctor” to “doctor”.
  4. To order by number of occurrences of occupation first and alphabetically by OCCUPATION second we can use ORDER BY COUNT(*), OCCUPATION.

 

MySQL

SELECT CONCAT('There are a total of ', COUNT(*), ' ', LOWER(OCCUPATION), 's.') 
FROM OCCUPATIONS 
GROUP BY OCCUPATION 
ORDER BY COUNT(*), OCCUPATION;

Oracle

SELECT 'There are a total of ' || COUNT(*) || ' ' || LOWER(OCCUPATION) || 's.' 
FROM OCCUPATIONS 
GROUP BY OCCUPATION 
ORDER BY COUNT(*), OCCUPATION;

Source – Hackerrank

Megha

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